Question

Al2O3 W(Al) -? W(O) -? Cr2O3 W(Cr) -? W(O) -? SO2 W(S) -? W(O) -? NH3 W(N) -? W(H) -?

Answer 1

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Объяснение:

Mr(Al2O3)=2Ar(Al)+3Ar(O)=2×27+3×16=102г/моль

w(Al)=n×Ar(Al)/Mr(Al2O3)=2×27/102=52%

w(O)=n×Ar(O)/Mr(Al2O3)=3×16/102=48%

также само и другие

Answer 2

To determine the weights of the elements in these compounds, we need to use their respective atomic masses from the periodic table.

Al2O3:

• W(Al) = 2 x atomic mass of Al = 2 x 26.98 g/mol = 53.96 g/mol
• W(O) = 3 x atomic mass of O = 3 x 16.00 g/mol = 48.00 g/mol

Cr2O3:

• W(Cr) = 2 x atomic mass of Cr = 2 x 52.00 g/mol = 104.00 g/mol
• W(O) = 3 x atomic mass of O = 3 x 16.00 g/mol = 48.00 g/mol

SO2:

• W(S) = atomic mass of S = 32.07 g/mol
• W(O) = 2 x atomic mass of O = 2 x 16.00 g/mol = 32.00 g/mol

NH3:

• W(N) = atomic mass of N = 14.01 g/mol
• W(H) = 3 x atomic mass of H = 3 x 1.01 g/mol = 3.03 g/mol

Therefore, the weights of the elements in the compounds are:

• Al2O3: W(Al) = 53.96 g/mol, W(O) = 48.00 g/mol
• Cr2O3: W(Cr) = 104.00 g/mol, W(O) = 48.00 g/mol
• SO2: W(S) = 32.07 g/mol, W(O) = 32.00 g/mol
• NH3: W(N) = 14.01 g/mol, W(H) = 3.03 g/mol