Question

C5H10(пентен-2 ) + HCL=?

Answer 1

CH3 - CH = CH - CH2 - CH3 + HCl ----> CH3 - CH2 - CHCl - CH2 - CH3

Образуется 3 - хлорпентан                                                                  

                                                                       

Answer 2

When pentene-2 (C5H10) reacts with hydrochloric acid (HCl), it undergoes an addition reaction known as an electrophilic addition. The reaction can occur in two possible ways, resulting in different products.

1. Markovnikov Addition: In this scenario, the hydrogen atom from HCl adds to the carbon atom with fewer hydrogen atoms in the pentene-2 molecule. The product formed is 2-chloropentane (C5H11Cl).

C5H10 + HCl → C5H11Cl

2. Anti-Markovnikov Addition: In this case, the hydrogen atom from HCl adds to the carbon atom with more hydrogen atoms in the pentene-2 molecule. This leads to the formation of 3-chloropentane (C5H11Cl).

C5H10 + HCl → C5H11Cl

Both products, 2-chloropentane and 3-chloropentane, are possible depending on the reaction conditions and reactant ratios.