Question

Cu So4-Cu(OH)2-CuO-Cu

Answer 1

CuSo4+2KoH—>Cu(Oh)2=K2So4
Cu(Oh)2–>CuO+H2O
CuO+2HCl—>CuCl2+H2O

Answer 2

The chemical equation you provided seems to represent a series of reactions involving copper sulfate (CuSO4), copper hydroxide (Cu(OH)2), copper(II) oxide (CuO), and elemental copper (Cu). Let's break it down step by step:

1. Copper sulfate (CuSO4): CuSO4 is a blue crystalline compound that contains copper in its +2 oxidation state. It can be obtained by dissolving copper oxide (CuO) or copper metal (Cu) in sulfuric acid (H2SO4). The equation for the reaction between copper oxide and sulfuric acid is: CuO + H2SO4 -> CuSO4 + H2O

2. Copper hydroxide (Cu(OH)2): Copper hydroxide is a greenish-blue solid that can be obtained by treating a copper sulfate solution with a base such as sodium hydroxide (NaOH). The equation for the reaction between copper sulfate and sodium hydroxide is: CuSO4 + 2NaOH -> Cu(OH)2 + Na2SO4

3. Copper(II) oxide (CuO): Copper(II) oxide is a black solid that can be obtained by heating copper metal in the presence of oxygen. The equation for this reaction is: 2Cu + O2 -> 2CuO

4. Elemental copper (Cu): Finally, if you heat copper(II) oxide strongly in the absence of oxygen, it can decompose to form elemental copper. The equation for this reaction is: 2CuO -> 2Cu + O2

So, to summarize the overall reaction pathway you provided: CuO + H2SO4 -> CuSO4 + H2O CuSO4 + 2NaOH -> Cu(OH)2 + Na2SO4 2Cu + O2 -> 2CuO 2CuO -> 2Cu + O2

These reactions demonstrate transformations between different forms of copper and can be used to synthesize or manipulate copper compounds.