Question

Помгите срочно пожалуйста. переведенно на русский

Answer 1

1)

дано

m(J₂)  = 2.54 g

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m(AgJ)=?

2AgJ--t-->2Ag+J₂

M(J₂) = 127 * 2 = 254 g/mol

n(J₂)= m(J₂) / M(J₂) = 2.54 / 254 = 0.01 mol

2n(AgJ) = n(J₂)

n(AgJ) = 0.01 * 2 = 0.02 mol

M(AgJ) = 235 g/mol

m(AgJ)  = n(AgJ) * M(AgJ) = 0.02 * 235 = 4.7 g

ответ 4.7 г

2)

дано

m(Fe2O3) = 55 g

m пр. (Fe) = 35 g

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m теор.(Fe)- ?

W(Fe)- ?

2Fe2O3-->4Fe+3O2

M(Fe2O3) = 160 g/mol

n(Fe2O3) = m(Fe2O3)  / M(Fe2O3) = 55 / 160 = 0.34375 mol

2n(Fe2O3)  = 4n(Fe)

n(Fe) = 4  * 0.34375 / 2 = 0.6875 mol

M(Fe) = 56 g/mol

m теор.(Fe) = n(Fe) * M(Fe) = 0.6875 * 56 = 38.5 g

W(Fe) = m пр.(Fe) / m теор.(Fe) * 100% = 35 / 38.5 * 100% = 90.9%

ответ 38.5 г , 90.9%