Question

ПОМОГИТЕ СРОЧНО!!!!!ПОДРОБНОЕ РЕШЕНИЕ!!! В браке рыжеволосой женщины (рецессивный признак) с группой крови 2 и темноволосого мужчины с группой крови 3 рыжеволосый мальчик с группой крови 1. Какова вероятность рождения у этой родительской пары рыжеволосой девочки с группой крови 4.

Answer 1

Ответ:

даже если брать группы крови как АА и ВВ , то всё равно рыжеволосой девочки с 4гоуппой не получается + взять АА и ВВ нельзя по той причине, что тогда по решению мы не найдем мальчика из условия задачи. и еще нужно учесть что 2+3 группа , то потомство любой группы

Answer 2

Probability of Birth Traits

To calculate the probability of a specific combination of traits in offspring, we need to consider the inheritance patterns of each trait separately. In this case, we have two traits to consider: hair color (red hair) and blood type.

Hair Color Inheritance

Hair color is determined by multiple genes, and the inheritance pattern can be complex. However, for the purpose of this question, let's assume that red hair is a recessive trait. This means that both parents must carry at least one copy of the gene for red hair in order for their child to have red hair.

Given that the mother is a red-haired woman (recessive trait) and the father is a dark-haired man, we can assume the following:

- The mother's genotype for hair color is rr (two copies of the recessive gene). - The father's genotype for hair color is Rr (one copy of the dominant gene and one copy of the recessive gene).

To determine the probability of having a red-haired child, we can use a Punnett square:

   |  r   r
---+--------
R  | Rr  Rr
r  | rr  rr

From the Punnett square, we can see that there is a 25% chance of having a child with red hair (rr genotype) when one parent is rr and the other parent is Rr.

Blood Type Inheritance

Blood type is determined by multiple genes as well. However, for simplicity, let's assume that blood type is determined by a single gene with three alleles: A, B, and O. The A and B alleles are codominant, while the O allele is recessive.

Given that the mother has blood type 2 and the father has blood type 3, we can assume the following:

- The mother's genotype for blood type is OO (two copies of the recessive O allele). - The father's genotype for blood type is AB (one copy of the A allele and one copy of the B allele).

To determine the probability of having a child with blood type 4, we can use a Punnett square:

   |  A   B
---+--------
O  | AO  BO
O  | AO  BO

From the Punnett square, we can see that there is a 0% chance of having a child with blood type 4 (AB genotype) when one parent is OO and the other parent is AB.

Conclusion

Based on the assumptions made about the inheritance patterns of hair color and blood type, the probability of this parental couple having a red-haired girl with blood type 4 is 0%. It is important to note that these calculations are based on simplified assumptions and may not reflect the true complexity of genetic inheritance.