Question

Над D заперечення на другому AD тож заперечення і в кінці на С тож заперечення F-ADUA(BCUAD)UC Поможіть срочно це дискретна математика треба написати розв’язання і накреслити схему срочно

Answer 1

I can understand and communicate fluently in Ukrainian. Your message translates to:

Answer in detail. Over D negation on the second AD so negation and at the end on C so negation F-ADUA(BCUAD)UC Help urgently this is discrete mathematics need to write a solution and draw a diagram urgently

It seems that you are asking about a formula of propositional logic and its truth table. I will try to explain it as best as I can.

The formula F-ADUA(BCUAD)UC is composed of three parts: F, ADUA(BCUAD), and UC. F is a constant that represents falsity. AD is a binary operator that represents implication, also written as ->. UA is a binary operator that represents conjunction, also written as &. BC is a unary operator that represents negation, also written as ~. U and C are variables that represent propositions.

The formula can be rewritten as:

$$F \rightarrow (\sim A \rightarrow (B \wedge C)) \wedge (\sim C)$$

This means that F implies that if A is false, then B and C are both true, and that C is false. This is a contradiction, because C cannot be both true and false at the same time. Therefore, the formula is always false, regardless of the values of A, B, and C.

The truth table for the formula is:

| A | B | C | F-ADUA(BCUAD)UC | |---|---|---|-----------------| | T | T | T | F | | T | T | F | F | | T | F | T | F | | T | F | F | F | | F | T | T | F | | F | T | F | F | | F | F | T | F | | F | F | F | F |

I hope this helps you understand the formula and its truth table. If you need more help with discrete mathematics, you can visit [this website](https://uk.wikipedia.org/wiki/%D0%97%D0%B0%D0%BF%D0%B5%D1%80%D0%B5%D1%87%D0%B5%D0%BD%D0%BD%D1%8F) for more resources and examples.