Question

В 800 г раствора содержится 50 г пищевой соли сколько соли содержится в 240 г раствора

Answer 1

Находим, сколько содержится соли в 1 грамме раствора:

50:800=0,0625 грамм.

Далее умножаем получившееся кол-во на 240 г.

0,0625x240=15 грамм.

Answer 2

В 100 г содержится 50:8 е соли.составим пропорцию ..800г-50г 240г-хг х=240*50:800=15(г) ответ :в 240г раствора 15г соли

Answer 3

To find out how much salt is present in 240 grams of the solution, we can use the concept of proportionality and set up a proportion based on the given information.

Let's assume that the amount of salt in the solution is directly proportional to the weight of the solution. We can set up the following proportion:

Amount of salt (in 800 g) / Weight of the solution (in 800 g) = Amount of salt (in 240 g) / Weight of the solution (in 240 g)

Mathematically, this can be represented as:

50 g / 800 g = x g / 240 g

To find the value of 'x' (the amount of salt in 240 g of the solution), we can cross-multiply and solve for 'x':

50 g * 240 g = 800 g * x

12000 g = 800 g * x

Now, isolate 'x' by dividing both sides by 800 g:

x = 12000 g / 800 g

x = 15 g

Therefore, there are 15 grams of salt in 240 grams of the solution.