Question

Int a b cb=2+(++c);a=(b--) *(2+(++b));c= --a + b++;​Programming language C

Answer 1

Ответ:

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Answer 2

It seems like you've provided a code snippet in the C programming language. Let's break down the code step by step and see what it does:

cCopy code
int a, b, c;
cb = 2 + (++c);
a = (b--) * (2 + (++b));
c = --a + b++;

Here's what's happening in each line:

1. int a, b, c;: This declares three integer variables a, b, and c.

2. cb = 2 + (++c);: It increments the value of c by 1 and then assigns the result (the new value of c) to cb. So, cb will be equal to 2 + (c + 1).

3. a = (b--) * (2 + (++b));: This line is a bit tricky because it involves both post-decrement (b--) and pre-increment (++b) operators. First, it calculates the right side of the assignment:

   • 2 + (++b) increments the value of b by 1 and then adds 2 to the new value.
   • b-- multiplies the current value of b with the result from the previous step and then decrements the value of b by 1. So, a will be equal to the result of this expression.

4. c = --a + b++;: This line first decrements the value of a by 1, then adds the new value of a to the current value of b, and finally, increments the value of b by 1. So, c will be equal to the result of this expression.

The specific values of a, b, and c depend on their initial values and the execution of these operations in the code. If you want to know the final values of these variables, you'll need to provide their initial values, and I can help you calculate the final values based on that information.