Question

(7-2/3)÷(1 3/4-1/6)*(1 1/5+2 2/3+1/6)=

Answer 1

Вот подробное решение. Надо уметь самому

Answer 2

To simplify the given expression, follow the order of operations (PEMDAS/BODMAS - Parentheses/Brackets, Exponents/Orders, Multiplication and Division, Addition and Subtraction):

1. Begin by simplifying the fractions within the expression:

   (7 - 2/3) ÷ (1 3/4 - 1/6) * (1 1/5 + 2 2/3 + 1/6)

   7 can be represented as a fraction: 7 = 21/3

   So the expression becomes:

   (21/3 - 2/3) ÷ (1 3/4 - 1/6) * (1 1/5 + 2 2/3 + 1/6)

2. Next, subtract the fractions:

   (19/3) ÷ (1 3/4 - 1/6) * (1 1/5 + 2 2/3 + 1/6)

3. Now, let's simplify the fractions in the denominators:

   1 3/4 can be written as (4/4 + 3/4) = 7/4 2 2/3 can be written as (3/3 + 2/3) = 5/3 1 1/5 can be written as (5/5 + 1/5) = 6/5

   The expression becomes:

   (19/3) ÷ (7/4 - 1/6) * (6/5 + 5/3 + 1/6)

4. Now, simplify the fraction inside the second set of parentheses:

   7/4 - 1/6 = (21/12 - 2/12) = 19/12

   The expression becomes:

   (19/3) ÷ (19/12) * (6/5 + 5/3 + 1/6)

5. Divide the fractions in the first set of parentheses:

   (19/3) ÷ (19/12) = (19/3) * (12/19) = 4

   The expression becomes:

   4 * (6/5 + 5/3 + 1/6)

6. Now, add the fractions inside the last set of parentheses:

   6/5 + 5/3 + 1/6 = (36/30 + 50/30 + 5/30) = 91/30

   The expression becomes:

   4 * (91/30)

7. Finally, multiply 4 by 91/30:

   4 * (91/30) = (4 * 91) / 30 = 364/30

Now, you can simplify 364/30 further by dividing both the numerator and denominator by their greatest common divisor, which is 2:

(364/2) / (30/2) = 182/15

So, the simplified result is 182/15.