Question

14 ромашек 6 маков и 7 ландышей собрали 3 одинаковых букетов .Сколько цветов оказалось в каждом букете

Answer 1

1) 14+6+7=27 (всего цветов)
2) 27:3=9 (в одном букете цветов)
Ответ: В одном букете 9 цветов

Answer 2

14+6+7=27 ( все цветы)
27 : 3 = 9 ( в одном букете)
ответ: 9

Answer 3

Solution:

To solve this problem, we can use algebra to represent the given information and then solve for the number of each type of flower in each bouquet.

Let's denote: - x as the number of daisies in each bouquet, - y as the number of poppies in each bouquet, and - z as the number of lilies in each bouquet.

Given: - 14 daisies, 6 poppies, and 7 lilies were used to make 3 identical bouquets.

We can set up the following system of equations: 1. x + y + z = 14 (total daisies) 2. x + y + z = 6 (total poppies) 3. x + y + z = 7 (total lilies)

We can solve this system of equations to find the values of x, y, and z.

Solution Steps:

1. Add the three equations together to get: 3x + 3y + 3z = 27. 2. Divide both sides of the equation by 3 to get: x + y + z = 9.

So, each bouquet contains 9 flowers in total. Since there are 3 bouquets, each type of flower is divided equally among the bouquets.

Answer:

Therefore, each bouquet contains: - 5 daisies, - 2 poppies, and - 2 lilies.