Question

(9x-y²)(9x+y²)=(5a²-3b)(5a²+3b)=(4m²+6n)(4m²-6n) =(1,3ab-1,1c)(1,3ab-1,1c)=

Answer 1

(9x-y²)(9x+y²)=81х^2-y^4
(5a²-3b)(5a²+3b)=25a^4-9b^2
(4m²+6n)(4m²-6n) =16m^4-36n^2
(1,3ab-1,1c)(1,3ab-1,1c)=1.69*a^2*b^2-1.21 c^2

^ - это степень

Answer 2

To simplify each of these expressions, let's use the difference of squares formula, which states that $(a^2 - b^2) = (a + b)(a - b)$:

1. $(9x - y^2)(9x + y^2)$

Apply the difference of squares formula: $(a^2 - b^2) = (a + b)(a - b)$ $(9x - y^2)(9x + y^2) = (9x)^2 - (y^2)^2 = 81x^2 - y^4$

2. $(5a^2 - 3b)(5a^2 + 3b)$

Apply the difference of squares formula: $(a^2 - b^2) = (a + b)(a - b)$ $(5a^2 - 3b)(5a^2 + 3b) = (5a^2)^2 - (3b)^2 = 25a^4 - 9b^2$

3. $(4m^2 + 6n)(4m^2 - 6n)$

Apply the difference of squares formula: $(a^2 - b^2) = (a + b)(a - b)$ $(4m^2 + 6n)(4m^2 - 6n) = (4m^2)^2 - (6n)^2 = 16m^4 - 36n^2$

4. $(1.3ab - 1.1c)(1.3ab - 1.1c)$

Apply the difference of squares formula: $(a^2 - b^2) = (a + b)(a - b)$ $(1.3ab - 1.1c)(1.3ab - 1.1c) = (1.3ab)^2 - (1.1c)^2 = 1.69a^2b^2 - 1.21c^2$

So, the simplified expressions are:

1. $81x^2 - y^4$
2. $25a^4 - 9b^2$
3. $16m^4 - 36n^2$
4. $1.69a^2b^2 - 1.21c^2$