Question

(х-3)²+(у+1)²=9 у=-1​

Answer 1

Ответ:

вот так обычно сделано

Answer 2

It seems like you've provided a system of equations and an equation. Let's break down the information you've given:

1. The equation "(x-3)² + (y+1)² = 9" represents a circle with its center at (3, -1) and a radius of 3.
2. The equation "y = -1" represents a horizontal line parallel to the x-axis at y = -1.

Since the value of y is fixed at y = -1, you can substitute this value into the equation of the circle to find the possible x-coordinates of the points where the circle intersects the line y = -1:

(x - 3)² + (-1 + 1)² = 9 (x - 3)² = 9 x - 3 = ±√9 x = 3 ± 3

This gives you two possible x-coordinates: x = 6 and x = 0. Therefore, there are two points of intersection between the circle and the line y = -1: (0, -1) and (6, -1).