Question

(5x-2y)(x+y)-5x^2 (4y-3) 3x^2+(3x+y)(y-x) 2y(11y-9)+0,5(16y^2-9) (x-5)(6+4x)-3(x^2-x+1) -x^2 (-x-2y+2)-〖x(x〗^2+1) x(1-x)+x(x^2-1) 5x^3+(y^2+5x)(xy-x^2 )пж​

Answer 1

Ответ:

Начинайте писать с 7 номера-это первый номер по Вашему

Объяснение:

Answer 2

Let's simplify each expression step by step:

1. (5x-2y)(x+y) - 5x^2(4y-3) = 5x(x+y) - 2y(x+y) - 20x^2y + 15x^2 = 5x^2 + 5xy - 2xy - 2y^2 - 20x^2y + 15x^2 = -17x^2y + 5x^2 + 3xy - 2y^2

2. 3x^2 + (3x+y)(y-x) = 3x^2 + 3xy - 3x^2 - y^2 + xy = 4xy - y^2

3. 2y(11y-9) + 0.5(16y^2-9) = 22y^2 - 18y + 8y^2 - 4.5 = 30y^2 - 18y - 4.5

4. (x-5)(6+4x) - 3(x^2-x+1) = 6x - 30 + 4x^2 - 20x - 3x^2 + 3x - 3 = x^2 - 11x - 33

5. -x^2(-x-2y+2) - x(x^2+1) = x^3 + 2xy - 2x^2 + x^3 + x = 2x^3 - 2x^2 + 2xy + x

6. x(1-x) + x(x^2-1) = x - x^2 + x^3 - x = x^3 - x^2

7. 5x^3 + (y^2+5x)(xy-x^2) = 5x^3 + xy^3 - x^3y + 5x^2y - 5x^3 = xy^3 - x^3y + 5x^2y

Note: I noticed that in the last expression you wrote "(y^2+5x)(xy-x^2 )пж​". I'm assuming "пж" was a typo and can be disregarded.