Question

Опредилите высоту объекта,если атмосферное давление на его вершине составило 460 мм.рт.ст,а у подножия было 710 мм рт.ст.

Answer 1

1)710-460=250 мм.рт.ст. - это разница
2)известно, что атм. давление на каждые 10 м понижается на 1 мм.рт.ст.
250×10=2500 м

Answer 2

Calculating the Height Based on Atmospheric Pressure

To calculate the height of an object based on the given atmospheric pressures at its summit and base, we can use the following formula:

h = (RT/g) * ln(P0/P)

Where: - h = height of the object - R = universal gas constant (8.314 J/(mol·K)) - T = average temperature of the air in Kelvin - g = acceleration due to gravity (9.81 m/s^2) - P0 = atmospheric pressure at the base - P = atmospheric pressure at the summit - ln = natural logarithm

Applying the Formula

Given: - Atmospheric pressure at the summit (P) = 460 mmHg - Atmospheric pressure at the base (P0) = 710 mmHg

We can convert the pressures to standard units (Pascals) and then use the formula to calculate the height of the object.

Conversion to Standard Units

1 mmHg = 133.322 Pa

So, - P = 460 mmHg = 61385.32 Pa - P0 = 710 mmHg = 94659.32 Pa

Calculating the Height

Using the formula: h = (RT/g) * ln(P0/P)

We need the average temperature of the air to calculate the height accurately. Since the average temperature is not provided, we will not be able to provide a precise calculation without this information.

If you have the average temperature of the air, we can proceed with the calculation using the provided formula.