Question

Ребзи!!! Хелп ми плиз!!!! John asked Lynn to change his dollar bill. Lynn told him that she had nine coins that added up to 1.09 dollars, but that she couldn't change his dollar. John then asked if she could change a half-dollar for him. She replied that she could not even change a quarter, dime or nickel. How many dimes did she have?

Answer 1

Lynn had 1 half-dollar, 1 quarter, 3  dimes and 4 cents.

Answer 2

To solve this problem, let's break it down step by step.

1. Lynn told John that she had nine coins that added up to 1.09 dollars. 2. She couldn't change John's dollar bill with those coins. 3. Lynn also mentioned that she couldn't change a half-dollar, quarter, dime, or nickel.

We need to determine how many dimes Lynn had. Let's start by assuming she had x dimes.

The value of x dimes is 0.10x dollars.

Since Lynn couldn't change a quarter, dime, or nickel, the remaining coins must add up to a value greater than or equal to 1.09 - 0.10x dollars.

Let's calculate the value of the remaining coins:

- Half-dollar: 0.50 dollars - Quarter: 0.25 dollars - Nickel: 0.05 dollars

The value of the remaining coins is 0.50 + 0.25 + 0.05 = 0.80 dollars.

Now, we can set up an equation to solve for x:

0.80 + 0.10x = 1.09

Simplifying the equation:

0.10x = 1.09 - 0.80 0.10x = 0.29

Dividing both sides of the equation by 0.10:

x = 0.29 / 0.10 x = 2.9

Since we can't have a fraction of a dime, we can conclude that Lynn had 2 dimes.

I hope this helps! Let me know if you have any further questions.