Question

Сколько секунд потребуется модему,передающему сообщение, со скоростью 28.800 бит в секунду,чтобы передать изображение размером 800 на 600,при условии что цвет кодируется 3 байтаминайти t?ПОМОГИТЕ

Answer 1

U = 28 800 бит/сек = 3600 байт/сек
V = 800*600*3 байт = 1 440 000 байт
t = V/U
t = 1 440 000 / 3600 = 400 сек = 6 мин 40 сек

Answer 2

Calculating Transmission Time for Modem

To calculate the transmission time for the modem to send an image, we can use the formula:

Time = Data / Rate

Where: - Time is the transmission time in seconds - Data is the size of the image in bits - Rate is the transmission speed in bits per second

Let's calculate the transmission time for the given scenario.

The size of the image can be calculated using the formula:

Size = Width x Height x Color Depth

Where: - Width is the width of the image in pixels - Height is the height of the image in pixels - Color Depth is the number of bytes used to represent a pixel's color

Given: - Width = 800 pixels - Height = 600 pixels - Color Depth = 3 bytes

Let's calculate the size of the image and then the transmission time.

Calculating Image Size

The size of the image can be calculated as follows:

Size = Width x Height x Color Depth

Size = 800 x 600 x 3 bytes

Size = 1,440,000 bytes

Calculating Transmission Time

Now, we can calculate the transmission time using the formula:

Time = Data / Rate

Given: - Data = 1,440,000 bytes (since 1 byte = 8 bits, the size in bits is 1,440,000 * 8) - Rate = 28,800 bits per second

Time = 1,440,000 * 8 / 28,800 seconds

Time ≈ 400 seconds

So, the modem, transmitting at a speed of 28,800 bits per second, would require approximately 400 seconds to transmit the 800x600 image, assuming each pixel's color is encoded in 3 bytes.