Question

Мощность алфавита равна 32. Сколько килобайт памяти потребуется, чтобы сохранить 150 страниц текста, содержащего в среднем 240 символов на каждой странице.

Answer 1

32 это 2 в 5 степени, значит 5 бит это 1 символ.

1) 240*150*5=180000 бит
 Теперь переводим в Кбайты
2) 180000:8:1024:1024=21,97

Answer 2

Calculating Memory Required to Store Text

To calculate the memory required to store 150 pages of text, each containing an average of 240 characters, given that the alphabet has 32 characters, we can use the following steps:

1. Calculate the Total Number of Characters: - Total characters = Number of pages * Average characters per page - Total characters = 150 * 240

2. Calculate the Total Number of Bits: - Total bits = Total characters * Bits per character - Total bits = Total characters * log2(32)

3. Convert Bits to Kilobytes: - Kilobytes = Total bits / 8 / 1024

Let's perform the calculations.

Calculation

1. Calculate the Total Number of Characters: - Total characters = 150 * 240 = 36,000 characters

2. Calculate the Total Number of Bits: - Total bits = 36,000 * log2(32) = 36,000 * 5 = 180,000 bits

3. Convert Bits to Kilobytes: - Kilobytes = 180,000 / 8 / 1024 ≈ 22.5 KB

So, to store 150 pages of text, each containing an average of 240 characters, using an alphabet of 32 characters, approximately 22.5 kilobytes of memory would be required.

This calculation is based on the formula for calculating the memory required to store text given the number of pages, average characters per page, and the size of the alphabet.

If you have any further questions or need additional assistance, feel free to ask!