Question

Вычислить S1=11₁₆+11₈+11₂=(11)hex+(11)oct+(11)bin=(??)dec S2=111₁₆+111₈+111₂=(111)hex+(111)oct+(111)bin=(??)decПомогите ,пожалуйста)))

Answer 1

$11_{16}=16+1=17_{10}\\ 11_8=8+1=9_{10}\\ 11_2=2+1=3_{10}\\ S_1=17+9+3=29_{10}$

Answer 2

Calculating S1 and S2

To calculate S1 and S2, we need to convert the given numbers from hexadecimal, octal, and binary to decimal and then add them together.

Converting Numbers to Decimal:

1. Converting 11₁₆ to decimal: - 11₁₆ = 1 * 16^1 + 1 * 16^0 = 17

2. Converting 11₈ to decimal: - 11₈ = 1 * 8^1 + 1 * 8^0 = 9

3. Converting 11₂ to decimal: - 11₂ = 1 * 2^1 + 1 * 2^0 = 3

Calculating S1: - S1 = 17 + 9 + 3 = 29

4. Converting 111₁₆ to decimal: - 111₁₆ = 1 * 16^2 + 1 * 16^1 + 1 * 16^0 = 273

5. Converting 111₈ to decimal: - 111₈ = 1 * 8^2 + 1 * 8^1 + 1 * 8^0 = 73

6. Converting 111₂ to decimal: - 111₂ = 1 * 2^2 + 1 * 2^1 + 1 * 2^0 = 7

Calculating S2: - S2 = 273 + 73 + 7 = 353

Therefore, S1 = 29 and S2 = 353.