Question

Дан фрагмент программы.Что появится на экране? var S:=0; for i:=1 to 4 do begin A[i]:=i^2-1 S:=s+A[i]; End; writeln(s);

Answer 1

Трассировочная таблица:
А1 0  
А2      3
А3           8
А4                  15
S 0     3    11    26
I   1     2   3       4
Ответ:26

Answer 2

Given Code Fragment:

```pascal var S:=0; for i:=1 to 4 do begin A[i]:=i^2-1; S:=s+A[i]; End; writeln(s); ```

Explanation:

The given code fragment is written in Pascal. Let's break it down step by step:

1. `var S:=0;` initializes a variable `S` with a value of 0. 2. `for i:=1 to 4 do` starts a loop that iterates from 1 to 4 (inclusive). 3. Inside the loop: - `A[i]:=i^2-1;` assigns the value of `i^2-1` to the array `A` at index `i`. This means that `A[1]` will be assigned the value of `1^2-1`, `A[2]` will be assigned the value of `2^2-1`, and so on. - `S:=s+A[i];` adds the value of `A[i]` to the variable `S`. 4. After the loop ends, `writeln(s);` prints the value of `S` to the screen.

Output:

To determine the output of the code, we need to calculate the value of `S` based on the given loop and array assignments:

- For `i=1`, `A[1]` will be assigned the value of `1^2-1`, which is 0. So, `S` becomes 0+0 = 0. - For `i=2`, `A[2]` will be assigned the value of `2^2-1`, which is 3. So, `S` becomes 0+3 = 3. - For `i=3`, `A[3]` will be assigned the value of `3^2-1`, which is 8. So, `S` becomes 3+8 = 11. - For `i=4`, `A[4]` will be assigned the value of `4^2-1`, which is 15. So, `S` becomes 11+15 = 26.

Therefore, the output of the code will be 26.

Example:

Here's an example of how the code would be executed and what would be displayed on the screen:

var S:=0;
for i:=1 to 4 do
begin
    A[i]:=i^2-1;
    S:=s+A[i];
End;
writeln(s);

Output: ``` 26 ```

Please let me know if you need any further assistance!