Question

Фотоальбом полностью занимает DVD объёмом 8 Гбайт. Сколько времени уйдёт на просмотр всех фотографий, если на просмотр одной фотографии уходит 7с (секунд) и каждая фотография занимает 500 Кбайт?

Answer 1

14000 с. (секунд). в 1 Гб 1000000 Кб.
1000000÷500=2000
2000×7=14000

Answer 2

Calculation of Time Required to View All Photos

To calculate the time required to view all the photos in the DVD photo album, we need to consider the size of each photo and the time it takes to view one photo.

Given: - DVD capacity: 8 GB - Size of each photo: 500 KB - Time to view one photo: 7 seconds

To calculate the number of photos that can fit on the DVD, we need to convert the DVD capacity from gigabytes (GB) to kilobytes (KB):

1 GB = 1024 MB = 1024 * 1024 KB = 1048576 KB

So, the DVD capacity in kilobytes is:

8 GB * 1048576 KB/GB = 8388608 KB

Next, we calculate the number of photos that can fit on the DVD:

8388608 KB (DVD capacity) / 500 KB (size of each photo) = 16777.216

Since we cannot have a fraction of a photo, we round down to the nearest whole number. Therefore, the DVD can hold 16777 photos.

To calculate the total time required to view all the photos, we multiply the number of photos by the time to view one photo:

16777 photos * 7 seconds/photo = 117439 seconds

To convert the time to a more understandable format, we can convert seconds to minutes and hours:

117439 seconds / 60 seconds/minute = 1957.32 minutes

1957.32 minutes / 60 minutes/hour = 32.62 hours

Therefore, it would take approximately 32.62 hours to view all the photos in the DVD photo album, assuming each photo takes 7 seconds to view and each photo occupies 500 KB of space.

Please note that these calculations are based on the given information and assumptions.