Question

Даны два текста, содержащих одинаковое количество символов. Первый текст состоит из алфавита мощностью 16 символов, а второй текст -256 символов. Во сколько раз информации во втором больше чем в первом? Если можно с Дано, Найти, Рещение? Даю 20 баллов!!! Срочно!!

Answer 1

Для кодирования одного из 16 символов требуется log(2)16=4 бита (2^4=16); для кодирования одного из 256 символов требуется log(2)256=8 бит (2^8=256). Так как количество символов в текстах одинаково, то объем информации во втором тексте в 8/4 = 2 раза больше, чем в первом.
Ответ: в 2 раза 

Answer 2

Given Information:

We are given two texts with the same number of characters. The first text consists of an alphabet with 16 characters, while the second text consists of 256 characters.

Solution:

To find out how much more information is in the second text compared to the first, we need to compare the number of possible combinations of characters in each text.

The first text has an alphabet with 16 characters, so the number of possible combinations is 16^N, where N is the number of characters in the text.

The second text has an alphabet with 256 characters, so the number of possible combinations is 256^N.

To find the ratio of the information in the second text to the first text, we can divide the number of possible combinations of the second text by the number of possible combinations of the first text:

Ratio = (256^N) / (16^N)

Since both texts have the same number of characters, N, we can simplify the ratio to:

Ratio = (256 / 16)^N = 16^2^N

Therefore, the information in the second text is 16^2^N times greater than the information in the first text.

Answer:

The information in the second text is 16^2^N times greater than the information in the first text.

Note: The value of N, the number of characters in each text, is not provided in the given information.