Question

с помощью цикла do while четные и нечетные числа в c++

Answer 1

Int  i = 0;
while(++i != 10) {
      if (!(i % 2)) cout << i << " ";
}

Answer 2

Using a Do-While Loop to Identify Even and Odd Numbers in C++

To use a do-while loop to identify even and odd numbers in C++, you can follow the steps below.

1. Initialize Variables: - Start by initializing variables for the number to be checked and for storing the result.

++
   int num; // Number to be checked
   int evenCount = 0; // Variable to count even numbers
   int oddCount = 0; // Variable to count odd numbers
   

2. Input the Number: - Prompt the user to input the number to be checked.

++
   cout << "Enter a number: ";
   cin >> num;
   

3. Do-While Loop: - Use a do-while loop to check if the number is even or odd and update the respective count variables.

++
   do {
       if (num % 2 == 0) {
           evenCount++; // Increment even count if the number is even
       } else {
           oddCount++; // Increment odd count if the number is odd
       }
       cout << "Enter another number (or 0 to exit): ";
       cin >> num;
   } while (num != 0);
   

4. Output the Results: - Display the counts of even and odd numbers entered by the user.

++
   cout << "Total even numbers entered: " << evenCount << endl;
   cout << "Total odd numbers entered: " << oddCount << endl;
   

This code prompts the user to enter numbers until they input 0, and it keeps track of the count of even and odd numbers entered.