Question

Скорость передачи данных через некоторое соединение равна 204800 бит/сек через данное соединение передают файл размером 1000 кбайт определите время передачи файла в секундах

Answer 1

V=2048*100 бит/с=2^11 * 4*25=25*2^13 бит/с
F=1000*2^13 бит=8*125*2^13=125*2^16 бит
t=F/v=125*2^16/(25*2^13)=5*2^3=5*8=40 c
ответ 40 с

Answer 2

Calculation of File Transfer Time

To calculate the time it takes to transfer a file, we need to consider the file size and the data transfer rate. In this case, the data transfer rate is given as 204,800 bits per second, and the file size is 1000 kilobytes.

To calculate the time in seconds, we can use the following formula:

Time (seconds) = File Size (bits) / Data Transfer Rate (bits per second)

Let's convert the file size from kilobytes to bits:

File Size (bits) = File Size (kilobytes) * 8 * 1024

Substituting the given values into the formula:

File Size (bits) = 1000 kilobytes * 8 * 1024 = 8,192,000 bits

Now we can calculate the time:

Time (seconds) = 8,192,000 bits / 204,800 bits per second

Calculating this, we get:

Time (seconds) = 40 seconds

Therefore, it would take approximately 40 seconds to transfer a file with a size of 1000 kilobytes at a data transfer rate of 204,800 bits per second.

Please note that the calculation assumes ideal conditions and does not account for any overhead or network congestion that may affect the actual transfer time.