Question

В книге 250 страниц. На каждой странице 60 строк, в каждой строке 80 символов. !!!!!Вычислить информационный объем книги (Кбайт) в 8-битной системе кодирования!!!!!

Answer 1

Ответ:

1200 Килобайта

Объяснение:

250×60=15.000 тысяч строк

15.000×80=1.200.000 миллионов символов

1.200.000×8=9.600.000 миллионов бит

9.600.000×0,000125=1200 Килобайт

Answer 2

Calculating the Information Volume of a Book

To calculate the information volume of the book, we need to consider the number of pages, lines per page, and characters per line. Given that the book has 250 pages, with 60 lines per page and 80 characters per line, we can calculate the information volume in kilobytes (KB) in an 8-bit encoding system.

First, let's calculate the total number of characters in the book:

Total number of characters = Number of pages × Lines per page × Characters per line

Total number of characters = 250 pages × 60 lines/page × 80 characters/line

Total number of characters = 1,200,000 characters

Now, to calculate the information volume in kilobytes (KB) in an 8-bit encoding system, we use the following formula:

Information Volume (KB) = Total number of characters / 8 / 1024

Information Volume (KB) = 1,200,000 characters / 8 / 1024

Information Volume (KB) ≈ 146.48 KB

Therefore, the information volume of the book in an 8-bit encoding system is approximately 146.48 KB.