Question

A=33 b=12 b=a//b+b c=a%b+a

Answer 1

Ответ:

Если вопрос по поводу Ошибок, то... Переменной <a> не существует, есть лишь переменная <A>.

Поэтому код должен выглядеть так:

a=33

b=12

b=a//b+b

c=a%b+a

~~~~ Или же так:

A=33

b=12

b=A//b+b

c=A%b+A

~~~~~ В общем результате Переменная <c> Равняется 38

Answer 2

Let's break down the given equations step by step:

1. A = 33: This sets the variable A equal to 33.

2. b = 12: This sets the variable b equal to 12.

3. b = a // b + b: In this equation, you're trying to set the value of b based on its current value and the value of a.

   First, let's substitute the values of a and b based on the previous assignments:

   • a is not assigned explicitly in your code, so we'll assume it's still 33 based on the initial assignment.
   • b is set to 12.

   Now, let's calculate the right-hand side of the equation:

   a // b means integer division of a by b, which is 33 // 12 = 2.

   So, the equation becomes: b = 2 + 12, which simplifies to b = 14.

   After this calculation, b is set to 14.

4. c = a % b + a: In this equation, you're trying to set the value of c based on the values of a and the updated value of b.

   • a is still 33.
   • b has been updated to 14 based on the previous calculation.

   Now, let's calculate the right-hand side of the equation:

   a % b means the remainder when a is divided by b, which is 33 % 14 = 5.

   So, the equation becomes: c = 5 + 33, which simplifies to c = 38.

   After this calculation, c is set to 38.

Here are the final values of the variables:

• A is 33.
• b is 14.
• c is 38.