Question

(1+1/1^2 )(1+1/2^2 )…(1+1/n^2 )

Answer 1

Если не Python, можете отметить нарушение.

Answer 2

The expression you provided is a product of terms that involve sums with fractions. Let's break it down step by step:

(1 + 1/1^2) * (1 + 1/2^2) * ... * (1 + 1/n^2)

Here, each term in the product is of the form (1 + 1/n^2). We can simplify this as follows:

(1 + 1/n^2) = (n^2/n^2 + 1/n^2) = ((n^2 + 1)/n^2)

So the expression becomes:

((1^2 + 1)/1^2) * ((2^2 + 1)/2^2) * ... * ((n^2 + 1)/n^2)

Now, you can simplify each of these terms individually:

(1^2 + 1)/1^2 = (1 + 1)/1 = 2/1 = 2

(2^2 + 1)/2^2 = (4 + 1)/4 = 5/4

...

(n^2 + 1)/n^2

So, the final product is:

(2/1) * (5/4) * ... * ((n^2 + 1)/n^2)

You can continue to multiply these fractions for each value of n, and the final result will be the product of these fractions. This is a series of fractions, and the value of the entire expression depends on the value of n. To get a specific numerical result, you would need to specify the value of n.