Question

СД объемом 700 Мб весит 15 г Сколько будет весить набор таких дисков необходимый для полного копирования информации жесткого диска объемом 320 Гбайт

Answer 1

320гбайт=327680мб

327680мб/мб700=469дисков

469дисков * 15г=7035г

7035г=7,04кг

Answer 2

To calculate the weight of the set of disks required for a full copy of the information on a 320 GB hard drive, we need to convert all the units to the same system. Let's use gigabytes (GB) for both the hard drive capacity and the CDs.

1 GB = 1000 MB 1 GB = 1000 * 1000 * 1000 bytes

First, let's convert the hard drive capacity from gigabytes to megabytes (MB): 320 GB * 1000 MB/GB * 1000 MB/GB = 320,000 MB

Next, let's find out how many CDs are required to hold 320,000 MB of data: Number of CDs = (320,000 MB) / (700 MB/CD) ≈ 457.14 CDs

Since you can't have a fraction of a CD, you would need to round up to the nearest whole number. This means you would need 458 CDs to hold the entire contents of the 320 GB hard drive.

Now, let's calculate the total weight of these CDs: Total weight = (Weight of 1 CD) * (Number of CDs) Total weight = 15 g/CD * 458 CDs ≈ 6,870 g

So, the set of CDs necessary for a full copy of the information on the 320 GB hard drive would weigh approximately 6,870 grams (or 6.87 kilograms).