Question

Растровое изображение размером 32*32 пикселя занимает 4 килобайта памяти. Определить максимальное количество цветов, используемых в изображении.

Answer 1

1024 цветов будет.

в одном пикселе один цвет

Answer 2

Дано:

K = 32 * 32 = 1024

V = 4 Кб * 1024 = 4 096 байт * 8 = 32 768 бит

Найти:

N - ?

Решение:

$N = 2^I\\V = K * I\\I = \frac{V}{K}\\I = \frac{32 768}{1024} = 32\\N = 2^{32} = 4 294 967 296$

Ответ: 4 294 967 296 цветов

Answer 3

To determine the maximum number of colors used in the 32x32-pixel raster image occupying 4 kilobytes of memory, we need to calculate the color depth of the image. The color depth is the number of bits used to represent each pixel's color.

Given that the image occupies 4 kilobytes of memory and has a size of 32x32 pixels, we can calculate the color depth as follows:

1 kilobyte (KB) = 1024 bytes 4 kilobytes (KB) = 4 * 1024 bytes = 4096 bytes

The image size in bytes is 4096 bytes.

Now, we can calculate the color depth (D) using the formula:

D = Image Size (in bits) / Total Number of Pixels

Each pixel's color is represented by D bits. To find the total number of pixels in a 32x32 image, we multiply the width and height:

Total Number of Pixels = 32 * 32 = 1024 pixels

Now, let's calculate the color depth:

D = 4096 bytes * 8 bits/byte / 1024 pixels D = 32768 bits / 1024 pixels D = 32 bits/pixel

The color depth of the image is 32 bits/pixel. This means that each pixel in the image is represented using 32 bits, which allows for 2^32 (4,294,967,296) unique color combinations.

Therefore, the maximum number of colors that can be used in the image is 4,294,967,296.