Question

А:=1; for i:=1 to 10 do A:=4+i Помогите!!

Answer 1

Ответ:

привет. после выполнения a=14

Answer 2

Sure, I'd be happy to help you understand the given code.

The code snippet you provided is written in a programming language with syntax similar to Pascal or Delphi. Let's break down what each line does:

1. A:=1;: This line initializes a variable A and assigns the value 1 to it.

2. for i:=1 to 10 do: This is a loop statement that iterates over the range of values from 1 to 10. During each iteration, the variable i takes the value of the current iteration.

3. A:=4+i: Inside the loop, this line updates the value of variable A. It takes the current value of A, adds the value of i (the current iteration number), and stores the result back into A. So, in each iteration, A is updated to 4 + i.

Let's see how the loop progresses:

1. Before the loop, A is initialized to 1.
2. In the first iteration (when i is 1), A becomes 4 + 1, so A is now 5.
3. In the second iteration (when i is 2), A becomes 4 + 2, so A is now 6.
4. This process continues until the last iteration (when i is 10), A becomes 4 + 10, so A is now 14.

At the end of the loop, the value of A will be 14.

So, the final value of A after executing the code will be 14.