Question

(Math.sqrt(Math.pow(x1-x2,2)+Math.pow(y1-y2,2)));

Answer 1

• Math.pow(x, y) возводит число x в степень y.
• Math.sqrt(x) извлекает квадратный корень из числа x.

Данную запись

$Math.sqrt(Math.pow(x1-x2,2)+Math.pow(y1-y2,2))$

можно представить как

$\sqrt{(x_1 - y_2)^2 + (y_1 - y_2)^2}$.

Это формула нахождения расстояния между двумя точками на координатной плоскости.

Answer 2

It looks like you've provided a mathematical expression that calculates the distance between two points in a two-dimensional space using the distance formula. Let's break down the components of the expression:

• Math.sqrt: This function calculates the square root of a given value.
• Math.pow(x1 - x2, 2): This part calculates the squared difference between the x-coordinates of two points (x1, y1) and (x2, y2).
• Math.pow(y1 - y2, 2): Similarly, this calculates the squared difference between the y-coordinates of the same two points.
• Math.sqrt(...) wraps around the sum of the squared differences, and gives you the final distance between the two points.

So, when you plug in the coordinates of two points (x1, y1) and (x2, y2) into this expression, it will calculate and return the distance between those two points using the Euclidean distance formula.