Question

A := -2; b = -3;a = b + a*3;if a <b then c:= a - belse c:=b-a;​

Answer 1

Ответ: Выходит - 6

Пошаговое объяснение :

a = -3 + (-2 * 3) = -3 + (-6) = -9

-9 < -3 => c = -9 - (-3) = - 9 + 3 = - 6

Answer 2

It appears that you've provided a small code snippet in a pseudocode-like format. Let's break down the code step by step:

1. A := -2; - This line sets the variable A to the value -2.

2. b = -3; - This line sets the variable b to the value -3.

3. a = b + a * 3; - This line updates the variable a by multiplying the current value of a by 3, adding the value of b, and assigning the result to a.

4. if a < b then - This is the start of a conditional statement.

5. c := a - b - If a is less than b, this line sets the variable c to the result of subtracting b from a.

6. else - This is the "else" part of the conditional statement, indicating what to do if the condition in step 4 is not met.

7. c := b - a; - If a is not less than b, this line sets the variable c to the result of subtracting a from b.

Here's a brief explanation of what this code does:

• It initializes A with the value -2 and b with the value -3.
• It then calculates a new value for a based on the values of a and b.
• Finally, it sets the value of c based on whether a is less than b. If a is less than b, it calculates c as a - b. If not, it calculates c as b - a.

Keep in mind that pseudocode is a way of representing algorithms in a more human-readable form, and it may not correspond to any specific programming language. If you have any specific questions or need further clarification, feel free to ask.