Question

Задача на phyton Есть шкаф со сторонами A,B,C(задаешь через инпут) и дверной проем со сторонами X,Y. Если шкаф пролезает в двурной проем то нужно написать YES,если нет то NO

Answer 1

Ответ:

Решение предполагает, что шкаф при необходимости можно пронести и уронив на бок

Объяснение:

   # Ширина и высота двери, размеры относятся друг к другу так: высота <= ширина <= длина

HoleW=0.0

HoleH=0.0

   # Ширина и высота шкафа (минимальные геометрические его размеры)

BrickW=0.0

BrickH=0.0

print("Введите размеры шкафа")

A = float(input())

B = float(input())

C = float(input())

print("Введите размеры двери")

D = float(input())

E = float(input())

  #Задаём размеры дверного проёма

if(D>E) :

   HoleW = D

   HoleH = E

else :

   HoleW = E

   HoleH = D

print ("Дверь W= " + str(HoleW) + " H=" + str(HoleH));

  #Задаём размер шкафа (эту часть конечно можно сделать более изящно, но лень)

if(A<=B and A<=C ) :

   BrickH = A

   if(B<C) :

       BrickW = B

   else:

       BrickW = C

if(B<=A and B<=C ) :

   BrickH = B;

   if(A<C) :

       BrickW = A

   else :

       BrickW = C

if(C<=A and C<=B ) :

   BrickH = C

   if(A<B) :

       BrickW = A

   else :

       BrickW = B

print ("Шкаф W=" + str(BrickW) + " H=" + str(BrickH) )

  #Сравниваем размеры двери и шкафа

if(BrickW<=HoleW and BrickH<=HoleH) :

   print ("YES")

else :

   print ("NO");

Answer 2

Problem Description

You have a cabinet with sides A, B, and C (specified through input) and a door frame with sides X and Y. Your task is to determine if the cabinet can fit through the door frame. If the cabinet can fit, output "YES"; otherwise, output "NO".

Solution in Python

To solve this problem, you can compare the dimensions of the cabinet and the door frame. If all sides of the cabinet are smaller than or equal to the corresponding sides of the door frame, then the cabinet can fit through the door frame.

Here's a Python code snippet that solves this problem:

def can_fit_cabinet(A, B, C, X, Y):
    # Check if all sides of the cabinet are smaller than or equal to the corresponding sides of the door frame
    if A <= X and B <= Y:
        return "YES"
    elif A <= Y and B <= X:
        return "YES"
    elif A <= X and C <= Y:
        return "YES"
    elif A <= Y and C <= X:
        return "YES"
    elif B <= X and C <= Y:
        return "YES"
    elif B <= Y and C <= X:
        return "YES"
    else:
        return "NO"

# Get the dimensions of the cabinet and the door frame from the user
A = int(input("Enter the length of side A of the cabinet: "))
B = int(input("Enter the length of side B of the cabinet: "))
C = int(input("Enter the length of side C of the cabinet: "))
X = int(input("Enter the length of side X of the door frame: "))
Y = int(input("Enter the length of side Y of the door frame: "))

# Check if the cabinet can fit through the door frame
result = can_fit_cabinet(A, B, C, X, Y)
print(result)

You can run this code by copying it into a Python environment or an IDE that supports Python, such as Jupyter Notebook or PyCharm. After running the code, you will be prompted to enter the dimensions of the cabinet and the door frame. The code will then determine if the cabinet can fit through the door frame and print "YES" or "NO" accordingly.

Please note that this code assumes that the sides of the cabinet and the door frame are all positive integers. If you need to handle other types of input, such as floating-point numbers or negative integers, you can modify the code accordingly.