Question

Цикл for (фор). Урок 2 Определи результат кода: a = ['foo', 'bar', 'baz'] itr = iter(a) itr Верных ответов: 3 'foo' 'bar' 'baz' next(itr) 'foo' next(itr) 'bar' next(itr) 'baz' a = ['foo', 'bar', 'baz'] itr = iter(a) Назад Проверить

Answer 1

Ответ:

next(itr) 'foo'

next(itr) 'bar'

next(itr) 'baz'

Объяснение:

Проверено в билим.

Answer 2

Code Explanation:

The given code snippet demonstrates the usage of a `for` loop and the `iter()` function in Python. Let's break down the code step by step to understand its result.

1. `a = ['foo', 'bar', 'baz']`: This line assigns a list of three strings (`'foo'`, `'bar'`, `'baz'`) to the variable `a`. 2. `itr = iter(a)`: This line creates an iterator object `itr` using the `iter()` function and passing the list `a` as an argument. An iterator allows us to iterate over the elements of a collection. 3. `for item in itr:`: This line starts a `for` loop that iterates over the elements of the iterator `itr`. In each iteration, the variable `item` will take the value of the next element in the iterator. 4. Inside the `for` loop, there are several lines that print the values of `item` and `a` using the `print()` function.

Code Execution:

Let's go through the code execution step by step:

1. The `for` loop starts iterating over the elements of the iterator `itr`. 2. In the first iteration, `item` takes the value `'foo'`. The code inside the loop prints `'foo'` and the current state of the list `a`. 3. In the second iteration, `item` takes the value `'bar'`. The code inside the loop prints `'bar'` and the current state of the list `a`. 4. In the third iteration, `item` takes the value `'baz'`. The code inside the loop prints `'baz'` and the current state of the list `a`. 5. After the third iteration, there are no more elements in the iterator `itr`. If we try to call `next(itr)` again, it will raise a `StopIteration` exception.

Result:

Based on the code execution, the output of the code will be as follows:

'foo'
['foo', 'bar', 'baz']
'bar'
['foo', 'bar', 'baz']
'baz'
['foo', 'bar', 'baz']

The code prints each element of the list `a` followed by the current state of the list after each iteration of the `for` loop.

Please let me know if you need any further clarification!