Question

Персональный компьютер имеет оперативную память 32Кбайта. Сколько страниц текста можно разместить в памяти этого компьютера, если на странице размещается 50 строк по 60 символов в каждой строке, а для хранения одного символа требуется 8 битов?

Answer 1

Ответ:

21

Объяснение:

1) Найдем объем одной строки:

60*8 = 240 бит

2) Тогда объем одной страницы равен:

50*240 = 12000 бит = 1500 байт = 1,46КБайт

3) Теперь же найдем кол-во страниц:

32:1,46 = 21,9 страниц, округляем в меньшую сторону и получаем 21.

Answer 2

Calculation of Pages in Computer Memory

To calculate the number of pages of text that can be stored in the computer's memory, we need to consider the following information:

- The computer has 32 kilobytes (KB) of random-access memory (RAM). - Each page contains 50 lines. - Each line has 60 characters. - Each character requires 8 bits of memory.

To calculate the number of pages, we can follow these steps:

1. Calculate the total number of bits available in the computer's memory: - 32 KB = 32,000 bytes = 256,000 bits (1 byte = 8 bits).

2. Calculate the number of characters that can be stored in the computer's memory: - Total bits available / bits per character = Total characters - 256,000 bits / 8 bits per character = 32,000 characters

3. Calculate the number of lines that can be stored in the computer's memory: - Total characters / characters per line = Total lines - 32,000 characters / 60 characters per line = 533.33 lines

4. Calculate the number of pages that can be stored in the computer's memory: - Total lines / lines per page = Total pages - 533.33 lines / 50 lines per page = 10.67 pages

Therefore, the computer can store approximately 10 pages of text in its memory.

Please note that the result is an approximation since we cannot have a fraction of a page. Additionally, this calculation assumes that there is no overhead or additional memory used for system operations or other data storage.