Цикл с параметром. Урок 1 Сопоставь данные. Количество соединений: 3 s=1 for i in range(4): s=6
s=s*i s=1 for i in range(1,4): s=15 s=s*i s=1 for i in range(1, 6, 2): s=0 s=s*i Помогите пожалуйста.Ответы на вопрос
Ответ:
я бы скрин дал но этот ноут не может
Объяснение:
там где:
for i in range (4) s=0
там где:
for i in range (1,4) s= 6
там где:
for i in range (1,6,2) s=15
Understanding the Code
Let's break down the code and understand what each line does:1. `s = 1` - This line initializes the variable `s` with a value of 1.
2. `for i in range(4):` - This line starts a loop that iterates 4 times, with `i` taking values from 0 to 3.
3. `s = 6 + s = s * i + s = 1` - This line performs multiple operations on the variable `s`: - `s = 6 + s` adds 6 to the current value of `s`. - `s = s * i` multiplies `s` by the current value of `i`. - `s = 1` assigns the value 1 to `s`.
4. `for i in range(1, 4):` - This line starts a loop that iterates 3 times, with `i` taking values from 1 to 3.
5. `s = 15 + s = s * i + s = 1` - This line performs similar operations as in line 3, but with different initial values: - `s = 15 + s` adds 15 to the current value of `s`. - `s = s * i` multiplies `s` by the current value of `i`. - `s = 1` assigns the value 1 to `s`.
6. `for i in range(1, 6, 2):` - This line starts a loop that iterates 3 times, with `i` taking values from 1 to 5 with a step of 2.
7. `s = 0 + s = s * i` - This line performs similar operations as in line 3 and 5, but with different initial values: - `s = 0 + s` adds 0 to the current value of `s`. - `s = s * i` multiplies `s` by the current value of `i`.
Evaluating the Code
Now, let's evaluate the code and see what values `s` takes after each iteration:1. After the first loop (`for i in range(4)`): - `s = 6 + s = s * i + s = 1` - The value of `s` after this loop is 6.
2. After the second loop (`for i in range(1, 4)`): - `s = 15 + s = s * i + s = 1` - The value of `s` after this loop is 15.
3. After the third loop (`for i in range(1, 6, 2)`): - `s = 0 + s = s * i` - The value of `s` after this loop is 0.
Conclusion
In conclusion, the code provided performs a series of calculations using a loop and updates the value of the variable `s` after each iteration. The final value of `s` depends on the specific operations performed in each loop.Похожие вопросы
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