Question

ПИТОН срочно Создайте из четных символов строки s1 строку s2 и из нечетных символов s3

Answer 1

procedure TForm1.Button1Click(Sender: TObject);

var

S1, S2, S3 : String;

i : Integer;

begin

S1 := Edit1.Text; //Исходная строка.

S2 := ''; //Строка из чётных символов строки S1.

S3 := ''; //Строка из НЕчётных символов строки S1.

for i := 1 to Length(S) do

if i mod 2 = 0 then

S2 := S2 + S1[i]

else

S3 := S3 + S1[i];

Edit2.Text := S2;

Edut3.Text := S3;

end;

Answer 2

Creating Strings from Even and Odd Characters in Python

To create two strings, s2 and s3, from the even and odd characters of a given string s1 in Python, you can use slicing. Here's a simple Python code to achieve this:

s1 = "your_given_string_here"
s2 = s1[1::2]  # Get the characters at odd indices
s3 = s1[::2]   # Get the characters at even indices

In this code: - `s1[1::2]` extracts the characters at odd indices from the string s1. - `s1[::2]` extracts the characters at even indices from the string s1.

For example, if s1 is "abcdef", then s2 will be "bdf" (characters at odd indices) and s3 will be "ace" (characters at even indices).

This code will work for any given string s1.

Let me know if you need further assistance with Python or anything else!