Question

Задать массив из 8 элементов целого типа. Заполнить массив случайными значениями из интервала (-10; 10) и вывести массив. Найти сумму и количество четных, а также произведение и количество нечетных значений элементов массива.

Answer 1

const z = 8;
var
  a: array[1..z] of integer;
  i, s, s2, n, n2: integer;
begin
  s := 0;
  s2 := 1;
  for i := 1 to z do begin
    a[i] := random(21) - 10;
    write(a[i], ' ');
    if(a[i] mod 2 = 0) then begin {четные}
      inc(n);
      s := s + a[i];
    end else begin
      inc(n2);
      s2 := s2 * a[i];
    end;
  end;
  writeln;
  writeln('Кол-во четных чисел: ', n, ', их сумма: ', s);
  writeln('Кол-во нечетных чисел: ', n2, ', их произведение: ', s2);
end.

Answer 2

Sure! Here's an example code in Python that creates an array of 8 integers, fills it with random values from the interval (-10, 10), and then calculates the sum and count of even numbers, as well as the product and count of odd numbers in the array:

pythonCopy code
import random

# Create an empty array of size 8
array = [0] * 8

# Fill the array with random values from -10 to 10
for i in range(len(array)):
    array[i] = random.randint(-10, 10)

# Print the array
print("Array:", array)

# Calculate the sum and count of even numbers
even_sum = 0
even_count = 0

# Calculate the product and count of odd numbers
odd_product = 1
odd_count = 0

for num in array:
    if num % 2 == 0:  # Check if the number is even
        even_sum += num
        even_count += 1
    else:
        odd_product *= num
        odd_count += 1

# Print the results
print("Sum of even numbers:", even_sum)
print("Count of even numbers:", even_count)
print("Product of odd numbers:", odd_product)
print("Count of odd numbers:", odd_count)

Each time you run this code, it will generate a new array with random values, calculate the required statistics, and display the results.