Question

Одноосновная карбоновая кислота, содержащая 26,1% углерода, 4,3% водорода, реагирует со спиртом с образованием вещества, плотность паров которого по воздуху равна 2,55. Установите формулу образовавшегося вещества.

Answer 1

Formula of the Substance Formed

To determine the formula of the substance formed when a monocarboxylic acid containing 26.1% carbon and 4.3% hydrogen reacts with alcohol, we need to analyze the given information.

According to the information provided, the substance formed has a vapor density of 2.55. Vapor density is the ratio of the density of a gas to the density of hydrogen gas at the same temperature and pressure. It is used to determine the molecular weight or formula of a substance.

To calculate the molecular weight or formula of the substance, we need to know the molar masses of carbon and hydrogen. The molar mass of carbon is approximately 12 g/mol, and the molar mass of hydrogen is approximately 1 g/mol.

Let's calculate the molar ratio of carbon to hydrogen in the substance formed:

- Carbon: 26.1% = 26.1 g - Hydrogen: 4.3% = 4.3 g

Now, let's calculate the number of moles of carbon and hydrogen:

- Moles of carbon = 26.1 g / 12 g/mol ≈ 2.175 mol - Moles of hydrogen = 4.3 g / 1 g/mol ≈ 4.3 mol

The molar ratio of carbon to hydrogen is approximately 1:2.

Based on the molar ratio, we can deduce that the formula of the substance formed is likely to be C1H2. However, we need to verify this information with additional sources to ensure accuracy.

Unfortunately, the search results did not provide specific information about the reaction between a monocarboxylic acid containing 26.1% carbon and 4.3% hydrogen and alcohol. Therefore, we cannot confirm the exact formula of the substance formed.

Please note that the given information is limited, and without further details, it is challenging to determine the precise formula of the substance formed.