Question

Помогите закончить уравнения реакций 2NaOH+CO2 NaOH+CuSO4 Cu(OH)2+K2SO4 Ba(OH)2+Na2SO4 AgNO3+NaCl Na2CO3+HCl

Answer 1

2NaOH + CO2 = Na2CO3 + H2O
2NaOH + CuSO4 = Cu(OH)2 + H2SO4
Cu(OH)2 + K2SO4 = CuSO4 + 2KOH
Ba(OH)2 + Na2SO4 = BaSO4 + 2NaOH
AgNO3+NaCl = AgCl + NaNO3
Na2CO3 + 2HCl = CO2 + H2O + 2NaCl

Answer 2

Balancing Chemical Equations

To balance the given chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's go through each equation step by step:

1. 2NaOH + CO2 → Na2CO3 + H2O

To balance this equation, we need to ensure that the number of sodium (Na), oxygen (O), carbon (C), and hydrogen (H) atoms is the same on both sides.

Let's start by balancing the carbon and oxygen atoms. Since there is only one carbon atom on the right side, we need to put a coefficient of 1 in front of CO2. This gives us:

2NaOH + CO2 → Na2CO3 + H2O

Next, let's balance the hydrogen atoms. There are two hydrogen atoms on the left side and two hydrogen atoms on the right side, so they are already balanced.

Finally, let's balance the sodium and oxygen atoms. There are two sodium atoms on the left side and two sodium atoms on the right side, so they are already balanced. However, there are three oxygen atoms on the right side (two from Na2CO3 and one from H2O), so we need to put a coefficient of 3 in front of Na2CO3. This gives us the balanced equation:

2NaOH + CO2 → Na2CO3 + H2O 2. NaOH + CuSO4 → Cu(OH)2 + Na2SO4

To balance this equation, we need to ensure that the number of sodium (Na), oxygen (O), copper (Cu), sulfur (S), and hydrogen (H) atoms is the same on both sides.

Let's start by balancing the copper, sulfur, and oxygen atoms. Since there is one copper atom on the left side and one copper atom on the right side, they are already balanced. Similarly, there is one sulfur atom on the left side and one sulfur atom on the right side, so they are also balanced. However, there are four oxygen atoms on the left side (two from NaOH and two from CuSO4), so we need to put a coefficient of 4 in front of Cu(OH)2. This gives us:

NaOH + CuSO4 → 4Cu(OH)2 + Na2SO4

Next, let's balance the sodium and hydrogen atoms. There is one sodium atom on the left side and two sodium atoms on the right side, so we need to put a coefficient of 2 in front of NaOH. This gives us:

2NaOH + CuSO4 → 4Cu(OH)2 + Na2SO4

Finally, let's balance the oxygen atoms. There are four oxygen atoms on the left side (two from NaOH and two from CuSO4) and four oxygen atoms on the right side (from 4Cu(OH)2), so they are already balanced. The balanced equation is:

2NaOH + CuSO4 → 4Cu(OH)2 + Na2SO4 3. Ba(OH)2 + Na2SO4 → BaSO4 + 2NaOH

To balance this equation, we need to ensure that the number of barium (Ba), oxygen (O), sulfur (S), sodium (Na), and hydrogen (H) atoms is the same on both sides.

Let's start by balancing the barium, sulfur, and oxygen atoms. Since there is one barium atom on the left side and one barium atom on the right side, they are already balanced. Similarly, there is one sulfur atom on the left side and one sulfur atom on the right side, so they are also balanced. However, there are four oxygen atoms on the left side (two from Ba(OH)2 and two from Na2SO4), so we need to put a coefficient of 4 in front of BaSO4. This gives us:

Ba(OH)2 + Na2SO4 → 4BaSO4 + 2NaOH

Next, let's balance the sodium and hydrogen atoms. There are two sodium atoms on the left side and two sodium atoms on the right side, so they are already balanced. However, there are four hydrogen atoms on the left side (two from Ba(OH)2) and two hydrogen atoms on the right side, so we need to put a coefficient of 2 in front of NaOH. This gives us:

Ba(OH)2 + Na2SO4 → 4BaSO4 + 2NaOH

The balanced equation is:

Ba(OH)2 + Na2SO4 → 4BaSO4 + 2NaOH 4. AgNO3 + NaCl → AgCl + NaNO3

To balance this equation, we need to ensure that the number of silver (Ag), nitrogen (N), chlorine (Cl), and sodium (Na) atoms is the same on both sides.

Let's start by balancing the silver and nitrogen atoms. Since there is one silver atom on the left side and one silver atom on the right side, they are already balanced. Similarly, there is one nitrogen atom on the left side and one nitrogen atom on the right side, so they are also balanced.

Next, let's balance the chlorine atoms. There is one chlorine atom on the left side and one chlorine atom on the right side, so they are already balanced.

Finally, let's balance the sodium atoms. There is one sodium atom on the left side and one sodium atom on the right side, so they are already balanced.

The balanced equation is:

AgNO3 + NaCl → AgCl + NaNO3 5. Na2CO3 + 2HCl → 2NaCl + H2O + CO2

To balance this equation, we need to ensure that the number of sodium (Na), carbon (C), oxygen (O), hydrogen (H), and chlorine (Cl) atoms is the same on both sides.

Let's start by balancing the sodium atoms. There are two sodium atoms on the left side and two sodium atoms on the right side, so they are already balanced.

Next, let's balance the carbon and oxygen atoms. Since there is one carbon atom on the left side and one carbon atom on the right side, they are already balanced. Similarly, there are three oxygen atoms on the left side (from Na2CO3 and H2O) and three oxygen atoms on the right side (from CO2 and NaCl), so they are also balanced.

Finally, let's balance the hydrogen and chlorine atoms. There are two hydrogen atoms on the left side and two hydrogen atoms on the right side, so they are already balanced. Similarly, there are two chlorine atoms on the left side and two chlorine atoms on the right side, so they are also balanced.

The balanced equation is:

Na2CO3 + 2HCl → 2NaCl + H2O + CO2 I hope this helps! Let me know if you have any further questions.