Question

Сколько молекул содержится в 5,6 г CO?какова масса 6,02x10*23 молекул NO?какова массу н.у 11,2 газа плотность которого 1,25г/л? помогите решить и напишите плиз решение чтобы остальное сама решила

Answer 1

1. Находим количествоСО  5,6/28 =0,2 моль         N(CO)  =   0,2*6,02*10*23 =1,204*10*23 молекул
2/Находим количество  n(NO)      6,02*10*23 /6,02*10*23 = 1моль
Находим массуm(NO) =  1*30 =30
3/    m = V p  11,2*1,25 =14г

Answer 2

Number of Molecules in 5.6 g of CO

To determine the number of molecules in 5.6 g of CO (carbon monoxide), we need to use the concept of molar mass and Avogadro's number.

1. Calculate the molar mass of CO: - The molar mass of carbon (C) is approximately 12.01 g/mol. - The molar mass of oxygen (O) is approximately 16.00 g/mol. - The molar mass of CO is the sum of the molar masses of carbon and oxygen: 12.01 g/mol + 16.00 g/mol = 28.01 g/mol.

2. Calculate the number of moles of CO: - Divide the given mass (5.6 g) by the molar mass of CO (28.01 g/mol): 5.6 g / 28.01 g/mol ≈ 0.1999 mol.

3. Calculate the number of molecules: - Use Avogadro's number, which is approximately 6.02 × 10^23 molecules/mol. - Multiply the number of moles by Avogadro's number: 0.1999 mol × 6.02 × 10^23 molecules/mol ≈ 1.20 × 10^23 molecules.

Therefore, there are approximately 1.20 × 10^23 molecules in 5.6 g of CO.

Mass of 6.02x10^23 Molecules of NO

To determine the mass of 6.02 × 10^23 molecules of NO (nitric oxide), we need to use the concept of molar mass and Avogadro's number.

1. Calculate the molar mass of NO: - The molar mass of nitrogen (N) is approximately 14.01 g/mol. - The molar mass of oxygen (O) is approximately 16.00 g/mol. - The molar mass of NO is the sum of the molar masses of nitrogen and oxygen: 14.01 g/mol + 16.00 g/mol = 30.01 g/mol.

2. Calculate the number of moles: - Divide the given number of molecules (6.02 × 10^23) by Avogadro's number (6.02 × 10^23 molecules/mol): 6.02 × 10^23 molecules / 6.02 × 10^23 molecules/mol = 1 mol.

3. Calculate the mass: - Multiply the number of moles by the molar mass of NO: 1 mol × 30.01 g/mol = 30.01 g.

Therefore, the mass of 6.02 × 10^23 molecules of NO is approximately 30.01 g.

Mass of 11.2 g of Gas with a Density of 1.25 g/L

To determine the volume of the gas, we can use the formula:

Volume (V) = Mass (m) / Density (d)

1. Given: - Mass (m) = 11.2 g - Density (d) = 1.25 g/L

2. Calculate the volume: - Divide the given mass (11.2 g) by the density (1.25 g/L): 11.2 g / 1.25 g/L = 8.96 L.

3. The volume of the gas is 8.96 L.

Please let me know if there's anything else I can help you with!