Question

Слили вместе 140мл 20%-го расствора HNO3(p=1,12г/мл)и 400 мл 15%-го расствора Ba(OH)2 (p=1,15г/мл) . Вычислить массовую долю в-в в полученном расстворе?

Answer 1

Надеюсь, все правильно

Answer 2

Calculation of the Mass Fraction in the Solution

To calculate the mass fraction in the solution, we need to determine the mass of each component in the solution and then calculate the total mass of the solution.

Given: - Volume of 20% HNO3 solution = 140 ml - Density of 20% HNO3 solution (p) = 1.12 g/ml - Volume of 15% Ba(OH)2 solution = 400 ml - Density of 15% Ba(OH)2 solution (p) = 1.15 g/ml

First, let's calculate the mass of HNO3 in the 20% solution: - Mass of HNO3 = Volume of solution * Density of solution - Mass of HNO3 = 140 ml * 1.12 g/ml = 156.8 g

Next, let's calculate the mass of Ba(OH)2 in the 15% solution: - Mass of Ba(OH)2 = Volume of solution * Density of solution - Mass of Ba(OH)2 = 400 ml * 1.15 g/ml = 460 g

Now, let's calculate the total mass of the solution: - Total mass of the solution = Mass of HNO3 + Mass of Ba(OH)2 - Total mass of the solution = 156.8 g + 460 g = 616.8 g

Finally, let's calculate the mass fraction of each component in the solution: - Mass fraction of HNO3 = (Mass of HNO3 / Total mass of the solution) * 100% - Mass fraction of HNO3 = (156.8 g / 616.8 g) * 100% ≈ 25.43%

- Mass fraction of Ba(OH)2 = (Mass of Ba(OH)2 / Total mass of the solution) * 100% - Mass fraction of Ba(OH)2 = (460 g / 616.8 g) * 100% ≈ 74.57%

Therefore, the mass fraction of HNO3 in the obtained solution is approximately 25.43%, and the mass fraction of Ba(OH)2 is approximately 74.57%.