Допоможіть будь ласка!!! ♥♥♥ Написати рівняння ряду перетворень і вказати тип реакції: 1.
BaSO4→BaO→Ba(OH)2→BaCl2 2.P2O5→H3PO4→K3PO4Ответы на вопрос
1) BaSO4 -> BaO + SO3 разложение
BaO + H2O = Ba(OH)2 соединение
Ba(OH)2 + 2HCl = BaCl2 + 2H2O обмен
2) P2O5 + 3H2O = 2H3PO4 соединение
H3PO4 + 3KOH = K3PO4 + 3H2O обмен
1. BaSO4 → BaO → Ba(OH)2 → BaCl2
The given series of transformations involves the compound BaSO4 being converted into BaO, then Ba(OH)2, and finally BaCl2. Let's analyze each step and determine the type of reaction involved.Step 1: BaSO4 → BaO In this step, BaSO4 is converted into BaO. This transformation involves the removal of sulfur and oxygen from the compound. It is a reduction reaction, as the oxidation state of sulfur decreases from +6 in BaSO4 to 0 in BaO.
Step 2: BaO → Ba(OH)2 In this step, BaO is converted into Ba(OH)2. This transformation involves the addition of water molecules to BaO, resulting in the formation of a hydroxide compound. It is a hydration reaction.
Step 3: Ba(OH)2 → BaCl2 In this step, Ba(OH)2 is converted into BaCl2. This transformation involves the replacement of hydroxide ions with chloride ions. It is a double displacement reaction, specifically a neutralization reaction.
Therefore, the overall series of transformations involves a reduction reaction, a hydration reaction, and a double displacement reaction.
2. P2O5 → H3PO4 → K3PO4
The given series of transformations involves the compound P2O5 being converted into H3PO4, and then into K3PO4. Let's analyze each step and determine the type of reaction involved.Step 1: P2O5 → H3PO4 In this step, P2O5 is converted into H3PO4. This transformation involves the addition of water molecules to P2O5, resulting in the formation of phosphoric acid. It is a hydration reaction.
Step 2: H3PO4 → K3PO4 In this step, H3PO4 is converted into K3PO4. This transformation involves the replacement of hydrogen ions with potassium ions. It is a double displacement reaction.
Therefore, the overall series of transformations involves a hydration reaction and a double displacement reaction.
I hope this helps! Let me know if you have any further questions.
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