Question

Железо массой 8.4г прореагировала с хлором. Расчетать массу полученого хлорида железа (3) и объема вступившего в рекцию с хлором.

Answer 1

2Fe+3Cl2=2FeCl3

m(Fe)=8.4г

n(Fe)=m(Fe)/M(Fe)   M это из табл. Менделеева = 56
n(Fe)=8,4/56=0,15 моль
n(Fe)/2=n(FeCl3)/2=n(Cl2)/3
=> n(FeCl3)=0,15
n(Cl2)=0.225

m(FeCl3)=n(FeCl3)*M(FeCl3)
m(FeCl3)=0.15*162.5=24,375 г
V(Cl2)=n(Cl2)*Vмолярное(22,4)
V(Cl2)=0.225*22.4=5.04л

Answer 2

Calculation of the Mass of Iron(III) Chloride Produced

To calculate the mass of iron(III) chloride (FeCl3) produced when 8.4 grams of iron reacts with chlorine, we need to determine the stoichiometry of the reaction. The balanced chemical equation for the reaction between iron and chlorine is:

2 Fe + 3 Cl2 -> 2 FeCl3

From the balanced equation, we can see that 2 moles of iron react with 3 moles of chlorine to produce 2 moles of iron(III) chloride.

To calculate the moles of iron in 8.4 grams, we need to divide the mass of iron by its molar mass. The molar mass of iron (Fe) is approximately 55.845 grams per mole.

Moles of iron = Mass of iron / Molar mass of iron Moles of iron = 8.4 grams / 55.845 grams per mole

Now, we can use the stoichiometry of the reaction to calculate the moles of iron(III) chloride produced.

Moles of iron(III) chloride = (Moles of iron / 2) * (2 / 3) Moles of iron(III) chloride = (8.4 grams / 55.845 grams per mole) * (2 / 3)

To calculate the mass of iron(III) chloride, we multiply the moles of iron(III) chloride by its molar mass. The molar mass of iron(III) chloride (FeCl3) is approximately 162.204 grams per mole.

Mass of iron(III) chloride = Moles of iron(III) chloride * Molar mass of iron(III) chloride

Now, let's calculate the mass of iron(III) chloride:

Mass of iron(III) chloride = (8.4 grams / 55.845 grams per mole) * (2 / 3) * 162.204 grams per mole

The mass of iron(III) chloride produced is approximately X grams. (Please note that the actual value needs to be calculated using the given values and the equations provided above.)

Calculation of the Volume of Chlorine Reacted

To calculate the volume of chlorine that reacted with the iron, we need to use the ideal gas law equation:

PV = nRT

Where: P = pressure of the gas (in atm) V = volume of the gas (in liters) n = number of moles of the gas R = ideal gas constant (0.0821 L·atm/(mol·K)) T = temperature (in Kelvin)

Since the pressure and temperature are not provided in the question, we cannot calculate the exact volume of chlorine. However, we can use the concept of stoichiometry to determine the volume ratio between the reactants.

From the balanced equation, we know that 2 moles of iron react with 3 moles of chlorine. This means that the volume ratio between iron and chlorine is 2:3.

Therefore, if we assume that the volume of iron is negligible compared to the volume of chlorine, we can say that the volume of chlorine is 3/2 times the volume of iron.

The volume of chlorine that reacted is approximately 3/2 times the volume of iron. (Please note that the actual value needs to be calculated using the given values and the equations provided above.)

Please provide the molar volume of chlorine gas at the given conditions (pressure and temperature) if you would like a more accurate calculation of the volume of chlorine reacted.