Question

Расставьте коэффициенты в схемах реакций методом электронного баланса. Укажите окислитель и восстановитель, также тип реакции 1)Ca+H2SO4-— CaSO4+SO2+H2O 2)Ca+H2SO4----CaSO4+S+H2O 3)Br2+CI2+H2O---HBrO3+HCI 4)Mg+KMnO4+H2SO4----MnSO4+MgSO4+K2SO4+H2O 5)NH4NO2----N2O+H2O Помогите пожалуйста

Answer 1

У вас последняя реакция неправильно написана
нитрита аммония не бывает, бывает только нитрат

Answer 2

Reaction 1: Ca + H2SO4 -> CaSO4 + SO2 + H2O

To balance this equation using the method of electron balance, we need to ensure that the number of electrons gained by the oxidizing agent is equal to the number of electrons lost by the reducing agent.

The balanced equation is as follows: 2Ca + H2SO4 -> CaSO4 + SO2 + 2H2O

In this reaction: - The oxidizing agent is H2SO4, which gains electrons. - The reducing agent is Ca, which loses electrons.

Reaction 2: Ca + H2SO4 -> CaSO4 + S + H2O

The balanced equation for this reaction is as follows: Ca + H2SO4 -> CaSO4 + S + H2O

In this reaction: - The oxidizing agent is H2SO4, which gains electrons. - The reducing agent is Ca, which loses electrons.

Reaction 3: Br2 + CI2 + H2O -> HBrO3 + HCI

The balanced equation for this reaction is as follows: Br2 + CI2 + 6H2O -> 2HBrO3 + 4HCI

In this reaction: - The oxidizing agent is Br2, which gains electrons. - The reducing agent is CI2, which loses electrons.

Reaction 4: Mg + KMnO4 + H2SO4 -> MnSO4 + MgSO4 + K2SO4 + H2O

The balanced equation for this reaction is as follows: 3Mg + 2KMnO4 + 4H2SO4 -> 2MnSO4 + 3MgSO4 + K2SO4 + 4H2O

In this reaction: - The oxidizing agent is KMnO4, which gains electrons. - The reducing agent is Mg, which loses electrons.

Reaction 5: NH4NO2 -> N2O + H2O

The balanced equation for this reaction is as follows: NH4NO2 -> N2O + 2H2O

In this reaction: - The oxidizing agent is NH4NO2, which gains electrons. - The reducing agent is not present in this reaction.

Please note that the above balanced equations have been derived using the method of electron balance.