Question

Помогите решить уравнение реакций 1. N2-NH3-NO-NO2-HNO3-KNO3 2.Ca3(PO4)2-P2-P2O5-HPO4-H3PO4-Ca3(PO4)2 Пожаааалуйста!!! Очень срочно надо❤❤❤

Answer 1

1)N2 + 3H2 = 2NH3 (условия: t,P,kat)
4NH3 + 5O2 = 4NO + 6H2O (условия: kat Pt)
2NO + O2 = 2NO2
4NO2 + O2 + 2H2O --> 4HNO3
KOH+HNO3(разб.)=KNO3+H2O
2)не знаю прости(

Answer 2

Balancing Chemical Equations

To balance the given chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's go through each equation step by step.

1. N2 - NH3 - NO - NO2 - HNO3 - KNO3

We start by balancing the nitrogen (N) atoms. There are two nitrogen atoms on the left side (N2) and one nitrogen atom in NH3. To balance this, we can put a coefficient of 2 in front of NH3:

N2 + 3H2 → 2NH3

Next, let's balance the hydrogen (H) atoms. There are six hydrogen atoms on the right side (2NH3), so we need to put a coefficient of 3 in front of H2:

N2 + 3H2 → 2NH3

Now, let's balance the oxygen (O) atoms. There are no oxygen atoms on the left side, but there are two oxygen atoms in HNO3. To balance this, we can put a coefficient of 2 in front of HNO3:

N2 + 3H2 + 2HNO3 → 2NH3

Finally, let's balance the potassium (K) and nitrogen (N) atoms. There is one potassium atom in KNO3 and one nitrogen atom in HNO3. To balance this, we can put a coefficient of 2 in front of KNO3:

N2 + 3H2 + 2HNO3 + 2KNO3 → 2NH3 + 2KNO3

The balanced equation is:

N2 + 3H2 + 2HNO3 + 2KNO3 → 2NH3 + 2KNO3

2. Ca3(PO4)2 - P2 - P2O5 - HPO4 - H3PO4 - Ca3(PO4)2

We start by balancing the phosphorus (P) atoms. There are two phosphorus atoms on the left side (Ca3(PO4)2) and two phosphorus atoms in P2O5. To balance this, we don't need to do anything.

Next, let's balance the oxygen (O) atoms. There are eight oxygen atoms on the right side (P2O5 and H3PO4), so we need to put a coefficient of 4 in front of H3PO4:

Ca3(PO4)2 + 4H3PO4 → P2O5 + H3PO4

Now, let's balance the hydrogen (H) atoms. There are twelve hydrogen atoms on the right side (4H3PO4), so we need to put a coefficient of 6 in front of H2O:

Ca3(PO4)2 + 4H3PO4 → P2O5 + 6H2O

Finally, let's balance the calcium (Ca) and phosphorus (P) atoms. There are three calcium atoms on the left side (Ca3(PO4)2) and two calcium atoms in Ca3(PO4)2. To balance this, we can put a coefficient of 2 in front of Ca3(PO4)2:

2Ca3(PO4)2 + 4H3PO4 → P2O5 + 6H2O

The balanced equation is:

2Ca3(PO4)2 + 4H3PO4 → P2O5 + 6H2O

I hope this helps! Let me know if you have any further questions.