Question

Определить молярную массу и молярную массу эквивалента Na2C2O4

Answer 1

Молярная 30*2+12*2+4*16=148

Answer 2

Molar Mass of Na2C2O4

To determine the molar mass of Na2C2O4, we need to calculate the sum of the atomic masses of all the atoms in the compound.

The molecular formula Na2C2O4 indicates that there are two sodium atoms (Na), two carbon atoms (C), and four oxygen atoms (O).

The atomic masses of these elements are as follows: - Sodium (Na) has an atomic mass of approximately 22.99 g/mol. - Carbon (C) has an atomic mass of approximately 12.01 g/mol. - Oxygen (O) has an atomic mass of approximately 16.00 g/mol.

To calculate the molar mass, we multiply the number of atoms of each element by its atomic mass and sum up the results:

Molar mass = (2 * Na) + (2 * C) + (4 * O)

Molar mass = (2 * 22.99 g/mol) + (2 * 12.01 g/mol) + (4 * 16.00 g/mol)

Calculating this expression gives us the molar mass of Na2C2O4:

Molar mass = 45.98 g/mol + 24.02 g/mol + 64.00 g/mol

Molar mass = 133.00 g/mol

Therefore, the molar mass of Na2C2O4 is approximately 133.00 g/mol.

Molar Mass Equivalent of Na2C2O4

The molar mass equivalent, also known as the equivalent mass, is the mass of a substance that is equivalent to one mole of the compound or ion in a specific reaction.

To determine the molar mass equivalent of Na2C2O4, we need to consider the reaction it is involved in. In this case, Na2C2O4 can act as a reducing agent and reduce certain substances, such as permanganate ions (MnO4-), in a redox reaction.

The molar mass equivalent for Na2C2O4 can be calculated by dividing the molar mass of Na2C2O4 by the number of electrons transferred in the reaction.

In the reaction between Na2C2O4 and MnO4-, the balanced equation is: 5 Na2C2O4 + 2 MnO4- + 16 H+ → 10 CO2 + 2 Mn2+ + 8 H2O + 10 Na+

From the balanced equation, we can see that 5 moles of Na2C2O4 react with 2 moles of MnO4-. This means that 5 moles of Na2C2O4 are equivalent to 2 moles of MnO4-.

To calculate the molar mass equivalent of Na2C2O4, we divide its molar mass by the ratio of moles between Na2C2O4 and MnO4-:

Molar mass equivalent = (Molar mass of Na2C2O4) / (Moles ratio)

Molar mass equivalent = 133.00 g/mol / (5/2)

Molar mass equivalent = 133.00 g/mol * (2/5)

Molar mass equivalent = 53.20 g/mol

Therefore, the molar mass equivalent of Na2C2O4 is approximately 53.20 g/mol.