Question

Cu+H2SO4 помогите пожалуйста

Answer 1

Cu+2H2SO4 =СиSO4 +SO2 +2Н2О
Си(0) -2е =Си(+2)  восстановитель. процесс окисления
S(+6) +2е =S(+4)окислитель. пр. восстановления
или так можно в зависимости от концентрации кислоты
4Cu +5H2SO4 =4СиSO4 +Н2S +4Н2О
Си(0) -2е =Си(+2)  восстановитель. процесс окисления
S(+6) +8е =S(-2)окислитель. пр. восстановления

3Cu +4H2SO4 =3СиSO4 +S +4Н2О
Си(0) -2е =Си(+2)  восстановитель. процесс окисления
S(+6) +6е =S(0)окислитель. пр. восстановления

Answer 2

Cu + H2SO4 refers to the reaction between copper (Cu) and sulfuric acid (H2SO4). When copper reacts with sulfuric acid, it undergoes a redox reaction, resulting in the formation of copper sulfate (CuSO4) and water (H2O). The balanced chemical equation for this reaction is:

Cu + H2SO4 → CuSO4 + H2O In this reaction, copper is oxidized from its elemental state (Cu) to copper(II) ions (Cu2+), while sulfuric acid is reduced from its elemental state (H2SO4) to water (H2O). The copper sulfate formed is a blue crystalline solid.

It's important to note that the reaction between copper and sulfuric acid is exothermic, meaning it releases heat. Additionally, sulfur dioxide gas (SO2) may also be produced as a byproduct of the reaction.

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