Question

Определить число отданных электронов: HNO2 - HNO3; PbO2 - PbSO4; HClO4 - ClO2; KMnO4 - MnO2; SO2 - K2SO4; NaBrO3 - Br2

Answer 1

E-электроны
1) N(+3)-2e =N(+5)
2)Pb(+4) +2e =Pb(+2)
3)Cl(+7)+3e =Cl(+4)
4)Mn(+7) +3e =Mn(+4)
5)S(+4) -2e =S(+6)
6)2Br(+5)+10e =2Br(0) (Здесь нужны коэффициенты ,потому что 2 атома Br)

Answer 2

Calculating the Number of Electrons Transferred

To determine the number of electrons transferred in each of the given chemical reactions, we can use the half-reaction method to balance the redox reactions and then count the electrons involved.

1. HNO2 - HNO3: - The balanced half-reaction for the oxidation of HNO2 to HNO3 involves the transfer of 5 electrons. - Source: 2. PbO2 - PbSO4: - The balanced half-reaction for the reduction of PbO2 to PbSO4 involves the transfer of 4 electrons. - Source: 3. HClO4 - ClO2: - The balanced half-reaction for the reduction of HClO4 to ClO2 involves the transfer of 10 electrons. - Source: 4. KMnO4 - MnO2: - The balanced half-reaction for the reduction of KMnO4 to MnO2 involves the transfer of 5 electrons. - Source: 5. SO2 - K2SO4: - The balanced half-reaction for the oxidation of SO2 to K2SO4 involves the transfer of 10 electrons. - Source: 6. NaBrO3 - Br2: - The balanced half-reaction for the reduction of NaBrO3 to Br2 involves the transfer of 6 electrons. - Source: In summary, the number of electrons transferred in the given reactions are as follows: - HNO2 - HNO3: 5 electrons - PbO2 - PbSO4: 4 electrons - HClO4 - ClO2: 10 electrons - KMnO4 - MnO2: 5 electrons - SO2 - K2SO4: 10 electrons - NaBrO3 - Br2: 6 electrons