Question

Определить степень окисления каждого элемента, расставьте коэффициенты методом электронного баланса Na+H2-> NaH

Answer 1

 2Na  +    H2  -> 2NaH
2Na(0) + H2(0) -> 2Na(+)H(-)
Na(0) -1e -> Na(+)    2     ок-ие
в-ль
H2(0) +2e -> 2H(-)   1     в-ие
ок-ль

Answer 2

2Na[0] + H2[0] = 2Na[+1]H[-1]
Na[0] - 1e = Na[+1] -- восстановитель, процесс окисление.
H2[0] + 2e = H2[-1] -- окислитель, процесс восстановление.

Answer 3

Determining Oxidation States and Balancing the Equation

To determine the oxidation states of each element in the equation Na + H2 -> NaH, we can follow a few guidelines:

1. The oxidation state of an element in its elemental form is always 0. 2. The sum of the oxidation states in a neutral compound is always 0. 3. The oxidation state of hydrogen (H) is usually +1, except when it is bonded to a metal, where it is -1. 4. The oxidation state of sodium (Na) is usually +1.

Based on these guidelines, we can determine the oxidation states as follows:

- The oxidation state of Na is +1. - The oxidation state of H in H2 is 0 since it is in its elemental form. - The oxidation state of H in NaH is -1 since it is bonded to a metal (Na).

To balance the equation using the method of electron balance, we need to ensure that the number of electrons gained by one element is equal to the number of electrons lost by another element.

In this case, we have one Na atom on the left side and one Na atom on the right side, so the number of Na atoms is already balanced.

Next, we have two H atoms on the left side and one H atom on the right side. To balance the hydrogen atoms, we can add a coefficient of 2 in front of NaH:

Na + H2 -> 2NaH

Now the equation is balanced with respect to both atoms and charge.

Final balanced equation: Na + H2 -> 2NaH

Please let me know if there's anything else I can help you with!