Question

Помогите с Химией. Даю 100 баллов! 1) H2 + N2 →NH3 2) CO +O2 → CO2 3) HNO3 → NO2+H2O+O2↑ а) Mg + N2 →Mg3N2 4) C +Cr2 O3→ CO2 +Cr 5) P + S →P2S3 6) KClO3 → KCl+ O2↑ 7) P2О5 + Н2О →Н3РО4 8) Cl2+Al → AlCl3 9) NaNO3 → NaNO2+O2↑ 10 ) KBr +Cl2 → KCl+ Br2

Answer 1

1) 3H2 + N2 →2NH3
2) 2CO +O2 → 2CO2
3) 4HNO3 → 4NO2+2H2O+O2↑ 
а) 3Mg + N2 →Mg3N2
4) 3C +2Cr2O3→ 3CO2 +4Cr
5) 2P + 3S →P2S3
6) 2KClO3 → 2KCl+ 3O2↑
7) P2О5 + 3Н2О →2Н3РО4
8) 3Cl2+ 2Al → 2AlCl3
9) 2NaNO3 → 2NaNO2+O2↑
10) 2KBr +Cl2 → 2KCl+ Br2

Answer 2

Balancing Chemical Equations

Sure! I can help you with balancing these chemical equations. Let's go through each equation one by one.

1) H2 + N2 → NH3

To balance this equation, we need to make sure that the number of atoms of each element is the same on both sides of the equation. In this case, we have 2 hydrogen atoms on the left side and 3 hydrogen atoms on the right side. To balance the hydrogen atoms, we can put a coefficient of 2 in front of NH3:

2H2 + N2 → 2NH3 [[1]]

2) CO + O2 → CO2

In this equation, we have 1 carbon atom on the left side and 1 carbon atom on the right side, so carbon is already balanced. However, we have 2 oxygen atoms on the left side and only 1 oxygen atom on the right side. To balance the oxygen atoms, we can put a coefficient of 2 in front of CO2:

CO + O2 → 2CO2 [[2]]

3) HNO3 → NO2 + H2O + O2↑

In this equation, we have 1 nitrogen atom on the left side and 1 nitrogen atom on the right side, so nitrogen is already balanced. However, we have 3 hydrogen atoms on the left side and only 2 hydrogen atoms on the right side. To balance the hydrogen atoms, we can put a coefficient of 2 in front of H2O:

HNO3 → NO2 + 2H2O + O2↑ [[3]]

a) Mg + N2 → Mg3N2

In this equation, we have 1 magnesium atom on the left side and 3 magnesium atoms on the right side, so magnesium is not balanced. To balance the magnesium atoms, we can put a coefficient of 3 in front of Mg:

3Mg + N2 → Mg3N2 [[4]]

4) C + Cr2O3 → CO2 + Cr

In this equation, we have 1 carbon atom on the left side and 1 carbon atom on the right side, so carbon is already balanced. However, we have 3 oxygen atoms on the left side and only 2 oxygen atoms on the right side. To balance the oxygen atoms, we can put a coefficient of 3 in front of CO2:

C + Cr2O3 → 3CO2 + Cr [[5]]

5) P + S → P2S3

In this equation, we have 1 phosphorus atom on the left side and 2 phosphorus atoms on the right side, so phosphorus is not balanced. To balance the phosphorus atoms, we can put a coefficient of 2 in front of P:

2P + S → P2S3 [[6]]

6) KClO3 → KCl + O2↑

In this equation, we have 1 potassium atom on the left side and 1 potassium atom on the right side, so potassium is already balanced. However, we have 3 oxygen atoms on the left side and only 2 oxygen atoms on the right side. To balance the oxygen atoms, we can put a coefficient of 3 in front of O2:

KClO3 → KCl + 3O2↑ [[7]]

7) P2O5 + H2O → H3PO4

In this equation, we have 2 phosphorus atoms on the left side and 1 phosphorus atom on the right side, so phosphorus is not balanced. To balance the phosphorus atoms, we can put a coefficient of 2 in front of H3PO4:

P2O5 + 3H2O → 2H3PO4 [[8]]

8) Cl2 + Al → AlCl3

In this equation, we have 2 chlorine atoms on the left side and 3 chlorine atoms on the right side, so chlorine is not balanced. To balance the chlorine atoms, we can put a coefficient of 2 in front of AlCl3:

Cl2 + 2Al → 2AlCl3 [[9]]

9) NaNO3 → NaNO2 + O2↑

In this equation, we have 1 nitrogen atom on the left side and 1 nitrogen atom on the right side, so nitrogen is already balanced. However, we have 3 oxygen atoms on the left side and only 2 oxygen atoms on the right side. To balance the oxygen atoms, we can put a coefficient of 3 in front of O2:

2NaNO3 → 2NaNO2 + 3O2↑ [[10]]

10) KBr + Cl2 → KCl + Br2

In this equation, we have 1 potassium atom on the left side and 1 potassium atom on the right side, so potassium is already balanced. We also have 1 bromine atom on the left side and 1 bromine atom on the right side, so bromine is already balanced. However, we have 2 chlorine atoms on the left side and only 1 chlorine atom on the right side. To balance the chlorine atoms, we can put a coefficient of 2 in front of KCl:

KBr + Cl2 → 2KCl + Br2 [[11]]

I hope this helps! Let me know if you have any further questions.